B^2+4B+40=0

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Solution for B^2+4B+40=0 equation:


Simplifying
B2 + 4B + 40 = 0

Reorder the terms:
40 + 4B + B2 = 0

Solving
40 + 4B + B2 = 0

Solving for variable 'B'.

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + 4B + -40 + B2 = 0 + -40

Reorder the terms:
40 + -40 + 4B + B2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + 4B + B2 = 0 + -40
4B + B2 = 0 + -40

Combine like terms: 0 + -40 = -40
4B + B2 = -40

The B term is 4B.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4B + 4 + B2 = -40 + 4

Reorder the terms:
4 + 4B + B2 = -40 + 4

Combine like terms: -40 + 4 = -36
4 + 4B + B2 = -36

Factor a perfect square on the left side:
(B + 2)(B + 2) = -36

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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